3.5 离散事件模拟

01离散事件


1、在日常生活中,经常会遇到许多为了维护社会正常秩序而需要排队的情景。这类活动的模拟程序通常需要用到队列和线性表之类的数据结构。

2、部分代码示例

//银行——离散事件模拟、
struct event{ int type,occurtime,money;//type为0,到达;为1,离开窗口;occurtime为0到600;
}ev1,ev2;
struct eventnode{ int type; int occurtime; int money; struct eventnode *next;
} *evlist;
struct queuenode{ int money,duringtime,arrivetime;//arrivetime用于最后计算总时间
 struct queuenode *next;
};
struct Queue{ struct queuenode *front; struct queuenode *rear;
}queue1,queue2;
int totaltime,customernum,closetime,timemark,totalmoney;
void evlistinsert(struct event temp){ struct eventnode *p1,*p2,*p3; p1=(struct eventnode *)malloc(sizeof(struct eventnode)); p1->type=temp.type; p1->occurtime=temp.occurtime; p1->money=temp.money; p1->next=NULL; if(!evlist){ evlist=p1; } else{ p2=evlist; while(p2->next)p2=p2->next; p2->next=p1; }
}
void arrive(){ int duringtime,intertime; ++customernum; duringtime=rand()%30+1; if(ev1.money+totalmoney>=0){//能满足
 struct queuenode *p; p=(struct queuenode*)malloc(sizeof(struct queuenode)); queue1.rear->next=p; queue1.rear=p; p->next=NULL; p->money=ev1.money; p->duringtime=duringtime; p->arrivetime=ev1.occurtime;//加入队列1
 printf("顾客%d\n到达时间:%d\n业务用时:%d\n金额:%d\n",customernum,ev1.occurtime,duringtime,ev1.money); ev2.type=1; ev2.occurtime=timemark+duringtime; timemark=ev2.occurtime; ev2.money=ev1.money; evlistinsert(ev2);//离开事件插入事件表
 totaltime+=ev2.occurtime-ev1.occurtime; } else{ struct queuenode *p; p=(struct queuenode *)malloc(sizeof(struct queuenode)); queue2.rear->next=p; queue2.rear=p; p->next=NULL; p->money=ev1.money; p->duringtime=duringtime; p->arrivetime=ev1.occurtime;//加入队列2
 printf("顾客%d\n到达时间:%d\n欲交易金额:%d,不能满足,进入队列2\n",customernum,ev1.occurtime,ev1.money); printf("-----------------------------------------------\n"); } intertime=rand()%10+1; ev2.type=0; ev2.occurtime=ev1.occurtime+intertime; ev2.money=rand()%10000-5000; if(ev2.occurtime>timemark)timemark=ev2.occurtime; if(ev2.occurtime<closetime&&timemark<closetime)evlistinsert(ev2);//下一个顾客
}
void leave(){ struct queuenode *p; if(ev1.type==1){ p=queue1.front->next; queue1.front->next=p->next; if(!queue1.front->next)queue1.rear=queue1.front; free(p);//删除队列1头的顾客
 totalmoney+=ev1.money; printf("离开时间:%d分钟\n银行金额:%d\n",ev1.occurtime,totalmoney); printf("-----------------------------------------------\n"); } if(ev1.money<0)return; struct queuenode *temp=queue2.front->next; if(!temp)return; int k=0,flag; while(temp!=NULL){ k++; temp=temp->next; } flag=k; k=0; int temptime=ev1.occurtime,tempmoney; temp=queue2.front->next; while(k<flag){ if(totalmoney+temp->money>=0){ tempmoney=temp->money; totalmoney+=temp->money; temptime+=temp->duringtime; totaltime+=temptime-temp->arrivetime; queue2.front->next=temp->next; if(!queue2.front->next)queue2.rear=queue2.front; temp=queue2.front->next; free(p);//删除队列2头的顾客
 printf("队列2有顾客离开了,时间为%d,交易金额为%d,银行金额为%d\n",temptime,tempmoney,totalmoney); printf("-----------------------------------------------\n"); } else if(temp->next){ queue2.front->next=temp->next; temp->next=NULL; queue2.rear->next=temp; queue2.rear=temp; temp=queue2.front->next;//队头掉到队尾
 } k++; } if(temptime>timemark)timemark=temptime; }
void openforday(){ queue1.front=(struct queuenode *)malloc(sizeof(struct queuenode)); queue1.rear=queue1.front; queue1.rear->next=NULL; queue2.front=(struct queuenode *)malloc(sizeof(struct queuenode)); queue2.rear=queue2.front; queue2.rear->next=NULL; totaltime=0; customernum=0; totalmoney=1000; closetime=1000; evlist=(struct eventnode*)malloc(sizeof(struct eventnode)); evlist->occurtime=0; evlist->type=0; evlist->money=5000;
}
int main(){ struct eventnode *p; srand(time(NULL)); openforday();//初始化
 while(evlist){ ev1.occurtime=evlist->occurtime; ev1.type=evlist->type; ev1.money=evlist->money; p=evlist; evlist=evlist->next; free(p); if(ev1.type==0)arrive(); else leave(); } struct queuenode *temp=queue2.front->next; while(temp){ totaltime+=closetime-temp->arrivetime; temp=temp->next; } printf("The average time is %f\n",(float)totaltime/customernum);
}
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文章来源: zhuanlan.zhihu.com,作者:小林C语言,版权归原作者所有,如需转载,请联系作者。

原文链接:zhuanlan.zhihu.com/p/337365654

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