反汇编一个简单的C程序并分析

C 源码：

int g(int x)
{ return x+1;
}

int f(int x)
{ return g(x);
}

int main(void)
{ return f(2) + 3;
}

汇编源码：

1 g:
2   pushl   %ebp
3   movl %esp, %ebp
4   movl 8(%ebp), %eax
5   addl $1, %eax
6   popl %ebp
7   ret
8 f:
9   pushl   %ebp
10  movl %esp, %ebp
11  subl $4, %esp
12  movl 8(%ebp), %eax
13  movl %eax, (%esp)
14  call g
15  leave
16  ret
17 main:
18  pushl   %ebp
19  movl %esp, %ebp
20  subl $4, %esp
21  movl $2, (%esp)
22  call f
23  addl $3, %eax
24  leave
25  ret